yaoxi-std 的博客

$\text{开}\mathop{\text{卷}}\limits^{ju\check{a}n}\text{有益}$

0%

P3357 最长k可重线段集问题

P3357 最长k可重线段集问题

题面

题目链接

解法

P3358的基础上,多出来了线段与$x$轴垂直的问题,如果和刚刚一样连边就会导致$i \to i$自环的问题。所以进行拆点,如果$l=r$则连接$in(l)$和$out(r)$,否则连接$out(l)$和$in(r)$。

AC代码

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
/**
* @file: P3357.cpp
* @author: yaoxi-std
* @url: https://www.luogu.com.cn/problem/P3357
*/
// #pragma GCC optimize ("O2")
// #pragma GCC optimize ("Ofast", "inline", "-ffast-math")
// #pragma GCC target ("avx,sse2,sse3,sse4,mmx")
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define resetIO(x) \
freopen(#x ".in", "r", stdin), freopen(#x ".out", "w", stdout)
#define debug(fmt, ...) \
fprintf(stderr, "[%s:%d] " fmt "\n", __FILE__, __LINE__, ##__VA_ARGS__)
template <class _Tp>
inline _Tp& read(_Tp& x) {
bool sign = false;
char ch = getchar();
long double tmp = 1;
for (; !isdigit(ch); ch = getchar())
sign |= (ch == '-');
for (x = 0; isdigit(ch); ch = getchar())
x = x * 10 + (ch ^ 48);
if (ch == '.')
for (ch = getchar(); isdigit(ch); ch = getchar())
tmp /= 10.0, x += tmp * (ch ^ 48);
return sign ? (x = -x) : x;
}
template <class _Tp>
inline void write(_Tp x) {
if (x < 0)
putchar('-'), x = -x;
if (x > 9)
write(x / 10);
putchar((x % 10) ^ 48);
}
template <const int MAXV, const int MAXE>
struct MCMF {
const int INF = 0x3f3f3f3f3f3f3f3f;
struct Edge {
int v, flow, cost;
} edge[MAXE * 2];
int tot = 1, head[MAXV], nxt[MAXE];
int flow, cost, cur[MAXV], dis[MAXV];
bool vis[MAXV];
void addedge(int u, int v, int flow, int cost) {
edge[++tot] = {v, flow, cost};
nxt[tot] = head[u], head[u] = tot;
edge[++tot] = {u, 0, -cost};
nxt[tot] = head[v], head[v] = tot;
}
bool spfa(int s, int t) {
fill(vis, vis + MAXV, 0);
fill(dis, dis + MAXV, -INF);
queue<int> que;
que.push(s);
dis[s] = 0;
vis[s] = 1;
while (!que.empty()) {
int u = que.front();
que.pop();
vis[u] = 0;
for (int i = head[u]; i; i = nxt[i]) {
int v = edge[i].v;
if (edge[i].flow && dis[v] < dis[u] + edge[i].cost) {
dis[v] = dis[u] + edge[i].cost;
if (!vis[v]) {
que.push(v);
vis[v] = 1;
}
}
}
}
return dis[t] != -INF;
}
int augment(int u, int t, int mx) {
if (u == t || mx == 0)
return mx;
vis[u] = 1;
int ret = 0;
for (int &i = cur[u]; i; i = nxt[i]) {
int v = edge[i].v;
if (vis[v] || dis[v] != dis[u] + edge[i].cost)
continue;
int tmp = augment(v, t, min(mx, edge[i].flow));
cost += tmp * edge[i].cost;
mx -= tmp, ret += tmp;
edge[i].flow -= tmp, edge[i ^ 1].flow += tmp;
if (mx == 0)
break;
}
vis[u] = 0;
return ret;
}
pair<int, int> mcmf(int s, int t) {
while (spfa(s, t)) {
copy(head, head + MAXV, cur);
flow += augment(s, t, INF);
}
return make_pair(flow, cost);
}
};
const int MAXN = 1e3 + 10;
const int MAXV = 2e3 + 10;
const int MAXE = 1e4 + 10;
const int INF = 0x3f3f3f3f3f3f3f3f;
int n, k, m, s, t, num, a[MAXN], l[MAXN], r[MAXN], p[MAXN], pt[MAXN][2];
MCMF<MAXV, MAXE> network;
signed main() {
read(n), read(k);
for (int i = 1; i <= n; ++i) {
int sx, sy, tx, ty;
read(sx), read(sy);
read(tx), read(ty);
if (sx > tx)
swap(sx, tx);
l[i] = sx, r[i] = tx;
p[++m] = l[i], p[++m] = r[i];
a[i] = sqrt((sx - tx) * (sx - tx) + (sy - ty) * (sy - ty));
}
p[++m] = -INF, p[++m] = INF;
sort(p + 1, p + m + 1);
m = unique(p + 1, p + m + 1) - p - 1;
for (int i = 1; i <= m; ++i)
pt[i][0] = ++num, pt[i][1] = ++num;
s = pt[1][0], t = pt[m][1];
for (int i = 1; i <= n; ++i) {
l[i] = lower_bound(p + 1, p + m + 1, l[i]) - p;
r[i] = lower_bound(p + 1, p + m + 1, r[i]) - p;
if (l[i] == r[i])
network.addedge(pt[l[i]][0], pt[r[i]][1], 1, a[i]);
else
network.addedge(pt[l[i]][1], pt[r[i]][0], 1, a[i]);
}
for (int i = 1; i <= m; ++i)
network.addedge(pt[i][0], pt[i][1], k, 0);
for (int i = 1; i < m; ++i)
network.addedge(pt[i][1], pt[i + 1][0], k, 0);
write(network.mcmf(s, t).second), putchar('\n');
return 0;
}